腾势D9流星腰线+璀璨紫，重新定义豪华MPV！

车界新潮涌动！

诸位看官，近来车市风云变幻，尤以MPV领域，昔日或被视作商用之器，今朝已焕发豪华之彩。

今日所瞩，腾势D9横空出世，竟令车坛为之侧目！

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翩若惊鸿，MPV亦可倾城

初见腾势D9，心头必生赞叹。

其π-motion势能美学，绝非空谈。

昔日MPV，或方正若匣，或臃肿如阜。

然D9之线条、之轮廓，宛若行云流水，一气呵成。

尤以那道流星轨迹腰线，自车首迤逦至车尾，恰似一道流动的光华，倍添动感。

再佐以一体贯穿式灯带，夜幕降临，华灯初上，其雍容气度，令人心驰神往。

尤为称道者，其璀璨紫之配色！

此名雅致，既蕴紫之尊贵神秘，又含璀璨之耀眼夺目。

日光之下，车身漆面流转溢彩，宛如一枚流动的宝石，摄人心魄。

而两侧对称的纵向π形符号灯组，则如点睛之笔，瞬间拔升整车的时尚品味与恢弘气度。

仅凭此貌，驻足之处，便已风华自具。

步入车内，奢华之风扑面而来。

15.6英寸中控巨屏与10.25英寸全液晶仪表盘相连，构成阔朗的视觉界面。

其搭载的腾势Link超智能交互系统，界面清爽，操作便捷，犹如操控新锐智能终端，响应灵敏。

更有腾势Share多屏互联、十种情景模式，试想一下，阖家出游，稚子于后排赏动画，您于前排导览，间或互动，其乐融融。

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轩敞天地，尽享偃仰之乐

凡购MPV者，无不期冀其空间宽裕，俾一家老小皆可安坐其间。

腾势D9于此道，堪称造诣精深。

5250mm的车身长度与3110mm的轴距，昭示其内部空间的 From the given information, we can write the following equations:

Let $x$ be the number of students who like both Math and Science.

Number of students who like Math = 30

Number of students who like Science = 20

Number of students who like at least one of Math or Science = 40

We know that the number of students who like at least one of the subjects is given by the formula:

$N(M \cup S) = N(M) + N(S) - N(M \cap S)$

where $N(M \cup S)$ is the number of students who like Math or Science or both, $N(M)$ is the number of students who like Math, $N(S)$ is the number of students who like Science, and $N(M \cap S)$ is the number of students who like both Math and Science.

Substituting the given values into the formula, we get:

$40 = 30 + 20 - x$

$40 = 50 - x$

To find the value of $x$, we can rearrange the equation:

$x = 50 - 40$

$x = 10$

So, there are 10 students who like both Math and Science.

Now, we can find the number of students who like only Math:

Number of students who like only Math = Number of students who like Math - Number of students who like both Math and Science

Number of students who like only Math = $30 - 10 = 20$

We can also find the number of students who like only Science:

Number of students who like only Science = Number of students who like Science - Number of students who like both Math and Science

Number of students who like only Science = $20 - 10 = 10$

To verify our answer, we can check if the sum of students who like only Math, only Science, and both is equal to the number of students who like at least one of the subjects:

Number of students who like only Math + Number of students who like only Science + Number of students who like both Math and Science = $20 + 10 + 10 = 40$

This matches the given information that 40 students like at least one of the subjects.

Final Answer: The final answer is $\boxed{10}$